Answer:
The horizontal force is 8.33N
Explanation:
In our case, the problem is a combination of Newton's 2nd Law of motion and Motion in a Straight Line.
For the formula:
1. We will use the formula [tex]v=v_{0} +at[/tex] to solve for the acceleration
where
[tex]v[/tex] is the final velocity, unit is in m/s
[tex]v_{0}[/tex] is the initial velocity, unit is in m/s
[tex]a[/tex] is the acceleration, unit is in m/[tex]s^2[/tex]
[tex]t[/tex] is the time interval for the movement of the object, unit is in seconds
2. To solve for the force, we will use the formula, F = ma
where
F is the force
m is the mass
a is the acceleration
For the given information
m = 25 kg
[tex]v_{0}[/tex] = 0 the grocery cart starts from rest
[tex]v[/tex] = 0.45 m/s
t = 1.35 seconds
Solving the problem
1. First, let us solve for the acceleration. Use the formula
[tex]v=v_{0} +at[/tex]
Then, substitute the given information, we have:
[tex]0.45m/s=0 +a(1.35s)[/tex]
Divide both sides of the equation [tex]1.35s[/tex], we have:
[tex]\frac{a(1.35s)}{1.35s} =\frac{0.45m/s}{1.35s}[/tex]
a = 0.33 m/[tex]s^2[/tex]
2. Now, we are ready to solve for the force. Use the formula
F = ma
Then substitute the given information
F = (25 kg)(0.33 m/[tex]s^2[/tex])
F = 8.33 N
Therefore, the horizontal force to accelerate the grocery cart is 8.33 N.
To learn more about this topic, just click on the following links:
- What happens to the force when the acceleration increases
https://brainly.ph/question/2220566
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- Law of motion between force and acceleration relationship
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