Answered

Makakuha ng detalyadong mga sagot sa lahat ng iyong katanungan sa IDNStudy.com. Sumali sa aming platform upang makatanggap ng mabilis at eksaktong tugon mula sa mga propesyonal sa iba't ibang larangan.

two pipes can empty a pool in 3 1/2 hours. if the smaller pipe can empty it in 14 hours alone, how long can the larger pipe empty the same pool alone?

Sagot :

Kaizoku00idn
let P the number of pool to be empty,S is speed,T is time   
P = S x T
smaller pipe 's speed is S
P=1, T =14
1 = S (14)
S = 1/14 pool per hour
bigger pipe's speed is S
let x the time of the bigger pipe to empty a pool , P=1
1= S x
S = 1/x pool per hour

together speed is (1/14) + (1/x) = (x/14x) + (14/14x) = (x+14)/14x pool per hour

back to the formula P = S x T
where P = 1 , T = 7/2 (together time 3 1/2 hour)
1 = [(x+14)/14x] (7/2)
manipulate the equation,
1 = (7x +98)/28x
28x = 7x + 98
28x -7x = 98
21x = 98
x = 98/21
x = 14/3 or 4 2/3
it takes 4 2/3 Hours to empty the pool by the bigger pipe  alone