Answered

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Guys try to solve this for me pls! The line in the center of the given it means OVER
I forgot the title but I have a example
Ex. a²+6a+5
_____________
a+1
= (a+5)(a+1)
____________=a+5
a+1

1.a³+2a²+a
____________
3a²+6a+3

2.3a²-6a
__________
a-2

3.a-1
______
1-a

4.(3a+2)(a+1)
_____________
3a²+5a+2

5.a³+125
_________
a²-25

6.a-8
______
8-a

7.a-8
______
a+8

8.18a²-3a
___________
-1+6a

9.3a-1
_______
1-3a

10.3a+1
________
1+3a

11.a²+10a+25
_____________
a+5

Sagot :

Riza1idn
[tex]1)\\\\\frac{a^3+2a^2+a}{3a^2+6a+3 }= \frac{a( a^2+2a +1)}{3( a^2+2a+1) }=\frac{a}{3} \\\\2)\\\\\frac{ 3a ^{2}-6a}{a-2}=\frac{ 3a(a -2)}{a-2}=3a[/tex]

[tex]3)\\\\\frac{ a-1}{1-a }= \frac{ a-1}{-( a-1) }= -1 \\\\4)\\\\\frac{(3a+2)(a+1)}{3a^2+5a+2}=\frac{(3a+2)(a+1)}{(a + 1) (3 a + 2)}=1[/tex]

[tex]5)\\\\\frac{a ^3+125 }{ a^2-25 }= \frac{a ^3+5^3 }{( a-5)(a+5) }=\frac{a ^3+5^3 }{( a-5)(a+5) }= \frac{(a+b)(a^2-5a+25^2)}{(a-b)(a+b)} =\\\\= \frac{ a^2-5a+25 }{ a-b }[/tex]

[tex]6)\\\\\frac{ a-8 }{8-a }= \frac{ -( 8-a ) }{8-a }=-1\\\\7)\\\\\frac{ a-8 }{a+8 }=\frac{ a+8-16 }{a+8 }=\frac{ a+8 }{a+8 }-\frac{16}{a+8}=1-\frac{16}{a+8}[/tex]

[tex]8)\\\\\frac{18a^2-3a }{-1+6a }= \frac{3a(6a -1) }{ 6a -1 }= 3a\\\\9)\\\\\frac{3a-1}{1-3a}=\frac{3a-1}{-( 3a-1)}=-1[/tex]

[tex]10)\\\\\frac{3a+1 }{1+3a }=\frac{3a+1 }{ 3a +1 }=1 \\\\11)\\\\\frac{a ^{2}+10a+25 }{a+5 }= \frac{(a +5 )^{2}}{a+5 }= a+5[/tex]


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