IDNStudy.com, kung saan nagtatagpo ang mga eksperto para sagutin ang iyong mga tanong. Ang aming platform ng tanong at sagot ay idinisenyo upang magbigay ng mabilis at eksaktong sagot sa lahat ng iyong mga tanong.

pa solve po i really need it....
[tex] \frac2{r-1} + \frac4{r-5} =7[/tex]


Sagot :

[tex] \frac2{r-1} + \frac4{r-5} =7 \\\\r-1\neq 0 \ \ \wedge \ \ r-5\neq 0\\\\r \neq 1 \ \ \wedge \ \ r \neq 5 \\\\D=R\setminus \left \{ 1,5 \right \} \\\\ \frac {2(r-5)+4(r-1)} {(r-1)(r-5) }=7 [/tex]

[tex]\frac { 4r-10+4r-4} {(r-1)(r-5) }=7\ \ |\ common \ denominator \\\\\frac { 6r-14} {(r^2-5r-r+5 ) }=7\\\\7(r^2-6r +5)=6r-14 \\\\ 7r^2-42r +35=6r-14 =0 \ \ |\ subtract\ 6r \ and \ add \ 14 \ to\ both\ sides \\\\ 7r^2-42r +35-6r+14 =0 [/tex]

[tex]7r^2-48r +49 =0\\a=7, \ \ b=-48, \ \ c=49 \\ Quadratic \ Formula : \\ \\r_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{48-\sqrt{ (-48)^2-4 \cdot 7\cdot 49}}{2 \cdot 7}=\frac{48-\sqrt{ 2304- 1372}}{14}=\\\\=\frac{48-\sqrt{932}}{14}=\frac{48-\sqrt{4\cdot 233}}{14}=\frac{48-2\sqrt{233}}{14}=\frac{2(24- \sqrt{233})}{14}=\frac{ 24- \sqrt{233} }{7} \\\\r_{1}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{ 24+ \sqrt{233} }{7}[/tex]