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The volume of Anand’s cube is 8 cubic inches. What is the total surface area, in square inches, of his cube?

Sagot :

vol of cube =    8 cu ins
thus length of 1 side of the cube  =   ∛8 = 2
Area of 1 surface = 2* 2= 4sq in
therefore total surface area = 4* 6 = 24sq ins    /  6  surfaces

[tex]volume = 8 \ in^3 \\ V= a^3 \\ where: \\"a" \ is \ the \ length \ of \ any \ edge \ of \ the \ cube. \\\\8=a^{3} \\a= \sqrt [3]{8 }\\a=2 \ in \\\\Surface \ Area \ of \ a \ Cube: \\\\ SA = 6 a^2\\\\SA=6\cdot 2^2=6\cdot 4=24 \ in^2[/tex]