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if  a die is thrown three times, what is the probability that all throws a six????

Sagot :

[tex]( \frac{1}{6}) ^{3} } = \frac{1}{216} [/tex]
the probability that a die would land on 6 would be 1/6 so for all three... you'd get 1/6, 1/6, 1/6. Multiply all of those or in short (1/6)^3 = 1/216