[tex]1) \\\\(2,3), \ \ y=-1 \\\\The \ slope \ of \ lines \ parallel \ is \ the \ same \\ \\ use \ y = mx + b \ and \ the \ point \ (2,3) \ to \ find \ b \\ \\ m=0, \ \ x=2, \ \ y=3\\\\3=0\cdot 2+b\\ \\ b=3 \\ \\y= 0\cdot x+3 \\ \\y=3 [/tex]
[tex]2. \\\\ x=-4 \ is \ a \ vertical \ line. \\ One \ vertical \ line \ is \ perpendicular \ to \ another \ vertical \ line.\\Therefore, \ the \ line \ that \ we \ are \ looking \ for \ is \ the \ horizontal \ line \ through \ (-5,7) \\\\ y = 7[/tex]
