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find the standard form of the equation m=-2/3 that passes through (-3,5)

Sagot :

Riza1idn
[tex] The\ slope \ intercept \ form:y=mx+b\\\\the\ slope\ m=-\frac{2}{3}\to y= -\frac{2}{3}x+b\\\\the\ point\ (-3;\ 5).\ Put\ x=-3\ and\ y=5\\ to\ equation\ of\ line:\\\\5= -\frac{2}{3}\cdot (-3)+b \\5=2+b \\b=5-2\\b=3 \\ \\ y=-\frac{2}{3}x +3[/tex]

[tex]y=-\frac{2}{3}x +3 \ \ / \cdot3 \\ \\3y=-2x+9 \\ \\2x+3y=9[/tex]


View image Riza1

all you need to follow is this formula: (y-y1)=m(x-x1)

your m will be -2/3 and your y1 will be 5 and your x1 is -3 so your solution is

(y-5)=-2/3(x+3)

after that distribute 3 to (y-5) and -2 to (x+3)

after distributing your answer will be 3y-15=-2x-6 after that transpose all

and that will be 2x+3y=-6+15 since its not yet done finish -6+15 that will be 9 so your standard form will be 2x+3y=9