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Sagot :
7x+5y=10
5y= -7x +10
y= -7/5x +2 to get the y intercept, let x = 0
thus y intercept = 2
to find the x intercept, let y = 0
thus x intercept = 2/(7/5) = 10/7
the slope is -7/10 & the trend of the line is decreasing
from left to right
5y= -7x +10
y= -7/5x +2 to get the y intercept, let x = 0
thus y intercept = 2
to find the x intercept, let y = 0
thus x intercept = 2/(7/5) = 10/7
the slope is -7/10 & the trend of the line is decreasing
from left to right
[tex]7x+5y=10 \\ the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\ 5y=-7x+10 \ \ /:5\\\\y=-\frac{7}{5}x+2 [/tex]
[tex]The \ slope \ is : \\\\ m=-\frac{5}{7}\\\\To \ get \ x-intercept, \ set \ y = 0 \\\\ 0=-\frac{7}{5}x+2 \ \ / \cdot 5\\\\0=-7x+10[/tex]
[tex]7x=10\ \ / : 7\\\\x=\frac{10}{7}\\\\To \ get \ y-intercept, \ set \ x = 0 \\\\y=-\frac{7}{5} \cdot 0+2 \\ \\y=2[/tex]
[tex]The \ slope \ is : \\\\ m=-\frac{5}{7}\\\\To \ get \ x-intercept, \ set \ y = 0 \\\\ 0=-\frac{7}{5}x+2 \ \ / \cdot 5\\\\0=-7x+10[/tex]
[tex]7x=10\ \ / : 7\\\\x=\frac{10}{7}\\\\To \ get \ y-intercept, \ set \ x = 0 \\\\y=-\frac{7}{5} \cdot 0+2 \\ \\y=2[/tex]
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