Time should be less than 1. Therefore, the total time is: (1300/R) - (1300/(R + 2)) < 1. We multiply both sides by (R)(R + 2) to remove the denominators. We have: (1300)(R + 2) - (1300)(R) < (R)(R + 2) --> 1300R + 2600 - 1300R < R^2 + 2R --> 0 < R^2 + 2R - 2600 --> 0 < (R - 50)(R + 52) --> Since there are no negative rates, we use: 0 < (R - 50) --> 50 < R (Original speed). Therefore, the train need to have a speed greater than 50 + 2 km/hr --> 52 km/hr.