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A cabinet is pulled across a cemented floor with a rope that makes an angle of 35 degrees with the floor. What is the component of the force parallel to the floor if a 90 N force is exerted? 

Sagot :

Indrawboyidn

The component of the force parallel to the floor: 73.724 N

Further explanation

Force is the pull or push that occurs to an object

The unit = N, Newton

Force itself is a vector that has magnitude and direction

Each vector can be described in two perpendicular vectors

The first vector is a vector component on the x-axis (Fx) and the second vector is a vector component on the y-axis (Fy)

Using the principle rules of cosines and sines in triangles then:

  • Fx = F cos θ
  • Fy = F sin θ

A cabinet is pulled across with a force of 90 N which is parallel to the floor and forms an angle of 35 degrees

Parallel means the direction of the x-axis, so we find the force in the horizontal direction (x)

• Force on horizontal components (Fx)

[tex]\rm Fx=F~cos~\theta\\\\Fx=90~cos~35^o\\\\Fx=\boxed{\bold{73,724~N}}[/tex]

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