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name a fraction equal to 3/7 whose numerator and denominator have a difference of 96
 


Sagot :

X / Y = 3 / 7 then 7X - 3Y =0; X = (3/7)Y; *since the denominator is bigger in the ratio (3/7), we use the equation: Y - X = 96. *plug the value of X in the 2nd equation: Y - (3/7)Y = 96; (4/7)Y = 96; Y = 168; X = (3/7)(168); X = 72; 72/168
3x/7x

7x-3x=96
4x/4=96/4
x=24

Substituting the value of x
3x/7x
3(24)/7(24)
= 72/168