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I URGENTLY NEED THIS. CAN YOU PLEASE HELP ME.
A basketball player throws a ball vertically with an initial velocity of 100ft/sec.
The distance of the ball from the ground after t seconds is given by the expression
100t – 16t².

1. What is the distance of the ball from the ground after 6 seconds?

2. After how many seconds does the ball reach a distance of 50 ft. from the ground?

3. How many seconds will it take for the ball to fall to the ground?

4. Do you think the ball can reach the height of 160 ft.? Why? Why not?

Sagot :

Kaiusidn
1. D(t) = 100t - 16t² D(6) = 100(6) - 16(6)^2 D(6) = 24 2. 50 = 100t - 16t² 16t² - 100t + 50 = 0 * use quadratic formula to find t T = 0.548, 5.701 3. 0 = 100t - 16t^2 0 = t (100 - 16t) T = 100/16 = 6.25 s 4. To solve for the max height, V^2 = initial V ^2 + 2ax (0)^2 = (100)^2 + 2(-32)(×) X = 156.25 Therefore, it is not possible to reach 160 ft because the max height that the ball can reach is 156.25 ft only.
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