Makahanap ng mga solusyon sa iyong mga problema sa tulong ng mga eksperto ng IDNStudy.com. Magtanong ng anumang bagay at makatanggap ng kumpleto at eksaktong sagot mula sa aming komunidad ng mga propesyonal.
I URGENTLY NEED THIS. CAN YOU PLEASE HELP ME. A basketball player throws a ball vertically with an initial velocity of 100ft/sec.
The distance of the ball from the ground after t seconds is given by the expression
100t – 16t².
1. What is the distance of the ball from the ground after 6 seconds?
2. After how many seconds does the ball reach a distance of 50 ft. from the ground?
3. How many seconds will it take for the ball to fall to the ground?
4. Do you think the ball can reach the height of 160 ft.? Why? Why not?
1. D(t) = 100t - 16t²
D(6) = 100(6) - 16(6)^2
D(6) = 24
2. 50 = 100t - 16t²
16t² - 100t + 50 = 0
* use quadratic formula to find t
T = 0.548, 5.701
3. 0 = 100t - 16t^2
0 = t (100 - 16t)
T = 100/16 = 6.25 s
4. To solve for the max height,
V^2 = initial V ^2 + 2ax
(0)^2 = (100)^2 + 2(-32)(×)
X = 156.25
Therefore, it is not possible to reach 160 ft because the max height that the ball can reach is 156.25 ft only.
Maraming salamat sa iyong pakikilahok. Patuloy na magbahagi ng iyong mga ideya at kasagutan. Ang iyong kaalaman ay mahalaga sa ating komunidad. Para sa mabilis at maasahang mga sagot, bisitahin ang IDNStudy.com. Nandito kami upang tumulong sa iyo.
