ANSWER:
40, 41, 42
EXPLANATION:
Let the first consecutive number be x
Let the second consecutive number be x + 1
Let the third consecutive number be x + 2
Since it's a sum, the numbers must be added
x + (x + 1) + (x + 2) = 123
remove the parenthesis
x + x + 1 + x + 2 = 123
add all the like terms
x + x + x + 1 + 2 = 123
3x + 3 = 123
subtract both sides by 3
3x + 3 - 3 = 123 - 3
3x = 120
divide both sides by 3
[tex]\frac{3x}{3} =\frac{120}{3}[/tex]
x = 40
First consecutive number = x
Second consecutive number = x + 1
Third consecutive number = x + 2
substitute the value of x in the expressions
x = 40
x + 1 = 40 + 1
= 41
x + 2 = 40 + 2
= 42
So the three consecutive numbers are 40,41, and 42
Checking:
40 + 41 + 42 = 123
81 + 42 = 123
123 = 123
Thus, 40,41, and 42 are the three consecutive number can be added to get a sum of 123
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