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bearing - trigonometry

question :

A ship sails N 27° 10' E for 39 km and then turns N 67° 50' W for 85 km. What is the distance and bearing of the ship from the starting point?

Please help~ thank you :)))


Sagot :

Imagine it as a triangle with sides A, B, C. α = 27° 10', β = 180 - (27° 10' + 67° 50) = 95°, ω = 67° 50'

sinα / a = sinω / c
0.457/85 = 0.926/c
c = 172.23 km