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1.(t.w) (x) = t(x) w(x)
=(3x² -2x-1) (2x-2
= 3x²-2x-1
=2x-2
?​

2.(u.w) (×) = u(×) w(×)
=(-2ײ+2×) (2×-2)
= -2ײ+2× =2×-2
?

3.(w.u) (×) = w(×) u(×) =
(2×-2) (-2ײ+2×)
= 2×-2
= -2ײ+2×
?​


Sagot :

Answer:

1.(t.w) (x) = t(x) w(x)

=(3x² -2x-1) (2x-2

= 3x²-2x-1

=2x-2
Answer:

(t⋅w)(x)=(3x² 2−2x−1)⋅(2x−2)
=(3x²*2x)+(3x²*-2x*−2)+(−2x*2x)+(−2x*−2)+(−1*2x)+(−1*−2)

=6x³ −6x²−4x² +4x−2x+2

(t⋅w)(x)=6x³−10x²+2x+2

2.(u.w) (×) = u(×) w(×)

=(-2ײ+2×) (2×-2)

= -2ײ+2× =2×-2

Answer:

(u⋅w)(x)=(−2x²+2x)⋅(2x−2)

=(−2x²*2x)+(−2x²* −2)+(2x*2x)+(2x*−2)
=−4x³ +4x ²+4x²−4x
(u⋅w)(x)=−4x³ +8x ²−4x

3.(w.u) (×) = w(×) u(×) =

(2×-2) (-2ײ+2×)

= 2×-2

= -2ײ+2×

Answer:
= (2×-2) (-2ײ+2×)

=(2x*−2x²)+(2x*2x)+(−2*−2x²)+(−2*2x)
=−4x ³ +4x² +4x² −4x
(u⋅w)(x)=−4x³ +8x²−4x