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Solve each QE by Extracting Square Roots​

Solve Each QE By Extracting Square Roots class=

Sagot :

Answer:

This is my answer i hope it helps

Step-by-step explanation:

1. To solve the equation x + 81 = 0, we subtract 81 from both sides to isolate x, giving us x = -81.

2. The inequality 2(x ≤ 5)33 is already solved, so the solution is x ≤ 5.

3. To solve the equation 3(4x - 1) - 1 = 11, we first distribute the 3 to get 12x - 3 - 1 = 11. Simplifying this gives us 12x - 4 = 11. Adding 4 to both sides gives us 12x = 15, and dividing by 12 gives us x = 3.

4. To solve the equation (2x - 3)^2 = 18, we first take the square root of both sides to get 2x - 3 = ±√18. Solving for x gives us x = 3 or x = -3.

5. To solve the equation 5x - 125 = 6, we add 125 to both sides to get 5x = 131, and then divide by 5 to get x = 25.

6. To solve the equation 4y - 100 = 0, we add 100 to both sides to get 4y = 100, and then divide by 4 to get y = 25.

7. To solve the equation 4x^3 = 250, we divide both sides by 4 to get x^3 = 62.5. Taking the cube root of both sides gives us x = 5.

8.To solve the equation 2x^2 = 4x - 8, we first rearrange to get 2x^2 - 4x + 8 = 0. Factoring gives us 2(x - 2)^2 = 0, so x = 2 or x = -2.

9. To solve the equation 5x - 125 = 6, we add 125 to both sides to get 5x = 131, and then divide by 5 to get x = 25.

10.To solve the equation 4y - 100 = 0, we add 100 to both sides to get 4y = 100, and then divide by 4 to get y = 25.

Correct me if im wrong

Thanks me later

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