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solve the following quadratic equation
1. 5x²-15x=0
2. 4x²=16
3. 2x²-12=0

pls paki sagot po nito ng tama need ko na po ​

Sagot :

Marcjhamezloreteroidn

Answer:

1. For the equation 5x² - 15x = 0:

First, factor out x: x(5x - 15) = 0

This equation can be rewritten as x(5(x - 3)) = 0

So, x = 0 or x - 3 = 0

Therefore, x = 0 or x = 3

Checking:

For x = 0: 5(0)² - 15(0) = 0, which is true.

For x = 3: 5(3)² - 15(3) = 45 - 45 = 0, which is also true.

2. For the equation 4x² = 16:

Divide both sides by 4: x² = 4

Taking the square root of both sides: x = ±√4

So, x = ±2

Checking:

For x = 2: 4(2)² = 16, which is true.

For x = -2: 4(-2)² = 16, which is also true.

3. For the equation 2x² - 12 = 0:

Add 12 to both sides: 2x² = 12

Divide by 2: x² = 6

Taking the square root of both sides: x = ±√6

Checking:

For x = √6: 2(√6)² - 12 = 2(6) - 12 = 0, which is true.

For x = -√6: 2(-√6)² - 12 = 12 - 12 = 0, which is also true.

So, the solutions to the quadratic equations are:

1. x = 0 or x = 3

2. x = 2 or x = -2

3. x = √6 or x = -√6

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