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Write each quadratic equation in standard form a * x ^ 2 + bx + c = 0 then identify the values of a, b, and c.
1. 3x - 2x² = 6x
2. (x + 3)(x + 4) + 0
3. (x + 2)² = 3(x + 2)
4. 2x(x + 4) = (x - 3)²​

Sagot :

Srichowchowidn

Step-by-step explanation:

1.) 3x-2x²=6x

(transpose to the right si -2x² then change sign to become positive 2x². same to positive 3x, transpose it to the right then change to negative to become -3x)

=2x²+6x-3x=0

after that, combine like terms such as 6x and -3x

=2x²+3x= 0

the value of a is the number with x², which is 2x².

the value of b is the number with a variable only, without the exponent, which is 3x.

and for c, the value of c is the number without exponent and variable. in this equation the value is zero mainly because it doesn't have a constant.

a=2, b=3, c=0

2.) (x+3)(x+4)=0

=x²+4x+3x+12=0

=x²+7x+12=0

a=1, b=7, c=12

3.)(x+2)²=3(x+2)

=(x+2)(x+2)=3x+6

=x²+4x+4=3x+6

=X²+4x-3x-6+4=0

=x²+x-2=0

a=1, b=1, c= -2

4.) 2x(x+4)=(x-3)²

=2x²+8x= (x-3)(x-3)

=2x²+8x= x²-6x+9

=2x²-x²+8x+6x-9=0

=x²+14x-9=0

a=1, b=14, c= -9