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how to solve 1st 8th term=an =3n+4 with solution​

Sagot :

Answer:

[tex] a_n = 3n + 4 \\ \\ a_1 = 3(1) + 4 \\a_1 = 3 + 4 \\ a_1 = 7 \\ \\ a_2 = 3(2) + 4 \\ a_2 = 6 + 4 \\ a_n2 = 10 \\ \\ a_3 = 3(3) + 4 \\ a_3 = 9 + 4 \\ a_3 = 13[/tex]

[tex]a_n = 3n + 4 \\ \\ a_4 = 3(4) + 4 \\ a_4 = 12 + 4 \\ a_4 = 16 \\ \\ a_5 = 3(5) + 4 \\ a_5 = 15 + 4 \\ a_5 = 19 \\ \\ a_6 = 3(6) + 4 \\ a_6 =18 + 4 \\ a_6 = 22 \\ [/tex]

[tex]a_n = 3n + 4 \\ \\ a_7 = 3(7) + 4 \\ a_7 = 21 + 4 \\ a_7 = 25 \\ \\ a_8 = 3(8) + 4 \\ a_8 = 24 + 4 \\ a_8 = 28[/tex]

Step-by-step explanation:

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