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find 50 term in the arithmetic sequence -3,0,6,3​

Sagot :

Answer:

147

Step-by-step explanation:

To find 50 terms in the arithmetic sequence -3, 0, 6, 3, we need to first determine the common difference in the sequence. The common difference (d) can be calculated by subtracting any term from the following term.

Given: -3, 0, 6, 3

1st term = -3

2nd term = 0

3rd term = 6

4th term = 3

Common difference (d) = 2nd term - 1st term = 0 - (-3) = 3

So, the common difference (d) is 3. Now we can generate the sequence:

1. -3

2. -3 + 3 = 0

3. 0 + 3 = 3

4. 3 + 3 = 6

5. 6 + 3 = 9

6. 9 + 3 = 12

7. 12 + 3 = 15

...

48. 141

49. 144

50. 147

The first 50 terms in the arithmetic sequence -3, 0, 6, 3 are: -3, 0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99, 102, 105, 108, 111, 114, 117, 120, 123, 126, 129, 132, 135, 138, 141, 144, 147.

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