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Can you explain how did you get the standard form 2x²-7x-22-0 in the question of (x-5) (2x+3) =7

Sagot :

Answer:

(x-5) (2x + 3) = 7

(use the FOIL Method)

Firsts: x•2x = 2x²

Outer: x•3 = 3x

Inner: -5•2x = -10x

Last: -5•3 = -15

combined them:

2x² + 3x - 10x -15 = 7

there is 2 linear term you need to subtract them:

2x² -7x -22 = 7

Transpose the seven into a constant so it will be equal to zero(it will change sign)

2x² -7x -22 -7 = 0

there is 2 constant term you need to subtract them

-22-7=-29

the final answer is:

2x² -7x -29 = 0 > standard form

a=2 b=-7 c=-29