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6ab² and 75a²b prime factorization solution please ​

Sagot :

Yankeriiiidn

Prime factorization of 6ab²:

6ab² = 2 * 3 * a * b * b

Prime factors: 2, 3, a, b

Prime factorization of 75a²b:

75a²b = 3 * 5² * a * a * b

Prime factors: 3, 5, a, a, b

In prime factorization, a number is expressed as a product of its prime factors. For 6ab², we break it down into 2 * 3 * a * b * b where 2, 3, a, and b are all prime factors. Similarly, for 75a²b, it is broken down into 3 * 5² * a * a * b with 3, 5, a, and b as prime factors. This process allows for simplification and deeper understanding of the number's components in terms of prime factors.

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