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A=5 B=3 C=-7
×= -b ±√b²-4ac


Sagot :

Answer:

Solve this quadratic equation using the quadratic formula:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

Given:

- ( A = 5 )

- ( B = 3 )

- ( C = -7 )

Substitute the values into the formula:

1. Calculate the discriminant:

[tex]\Delta = b^2 - 4ac[/tex]

[tex]\Delta = (3)^2 - 4(5)(-7)[/tex]

[tex]\Delta = 9 + 140[/tex]

[tex]\Delta = 149[/tex]

2. Solve for ( x ):

[tex]x = \frac{-b \pm \sqrt{\Delta}}{2a}[/tex]

[tex]x = \frac{-3 \pm \sqrt{149}}{2 \cdot 5}[/tex]

[tex]x = \frac{-3 \pm \sqrt{149}}{10}[/tex]

Therefore, the solutions are:

[tex]x_1 = \frac{-3 + \sqrt{149}}{10}[/tex]

[tex]x_2 = \frac{-3 - \sqrt{149}}{10}[/tex]

These are the roots of the quadratic equation

[tex](5x^2 + 3x - 7 = 0\).[/tex]