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A sugar solution with a mass of 300 g has a percent by mass concentration of 20%.How much the sugar is present in this solution if 240g of water is used? A. 40g B. 50g C. 60g D. 66g​

Sagot :

HelperWarsidn

Answer:

C. 60g

Explanation:

To find out how much sugar is present in a solution with a given percent by mass concentration, you can use the formula:

Mass of solute (sugar)

=

Percent by mass

×

Total mass of solution

Mass of solute (sugar)=Percent by mass×Total mass of solution

Given:

Percent by mass concentration = 20%

Total mass of the solution = 300 g

Mass of sugar

=

20

100

×

300

 g

Mass of sugar=

100

20

×300 g

Mass of sugar

=

0.2

×

300

 g

Mass of sugar=0.2×300 g

Mass of sugar

=

60

 g

Mass of sugar=60 g

So, the mass of sugar present in the solution is 60 grams.