Sumali sa IDNStudy.com para sa detalyadong mga sagot sa iyong mga tanong. Ang aming komunidad ay handang magbigay ng malalim at praktikal na mga solusyon sa lahat ng iyong mga katanungan.
Sagot :
Answer:
⚠️ Don't copy like these < / p> < p > p >
[tex]1. \: \(1 \frac{3}{2} + 1 \frac{3}{5} [/tex]
[tex]1 \frac{3}{2} = 1 + \frac{3}{2} = \frac{5}{2}\\
1 \frac{3}{5} = 1 + \frac{3}{5} = \frac{8}{5}\\
\text{Convert to a common denominator:}\\
\frac{5}{2} = \frac{25}{10}\\
\frac{8}{5} = \frac{16}{10}\\
\frac{25}{10} + \frac{16}{10} = \frac{41}{10} = 4 \frac{1}{10} [/tex]
[tex]2. \: \(\frac{2}{11} + 2 \frac{1}{2} [/tex]
[tex]2 \frac{1}{2} = 2 + \frac{1}{2} = \frac{5}{2}\\
\text{Convert to a common denominator:}\\
\frac{2}{11} + \frac{5}{2} = \frac{2 \cdot 2 + 5 \cdot 11}{2 \cdot 11} = \frac{4 + 55}{22} = \frac{59}{22} = 2 \frac{15}{22} [/tex]
[tex]3. \: \(1 \frac{1}{3} + \frac{1}{5}[/tex]
[tex]1 \frac{1}{3} = 1 + \frac{1}{3} = \frac{4}{3}\\
\text{Convert to a common denominator:}\\
\frac{4}{3} + \frac{1}{5} = \frac{4 \cdot 5 + 1 \cdot 3}{3 \cdot 5} = \frac{20 + 3}{15} = \frac{23}{15} = 1 \frac{8}{15}[/tex]
[tex]4. \: \(2 \frac{3}{4} + \frac{2}{2}
[/tex]
[tex]2 \frac{3}{4} = 2 + \frac{3}{4} = \frac{11}{4}\\
\frac{2}{2} = 1\\
\frac{11}{4} + 1 = \frac{11}{4} + \frac{4}{4} = \frac{15}{4} = 3 \frac{3}{4}[/tex]
[tex]5. \: \(1 \frac{1}{2} + \frac{2}{3}[/tex]
[tex]1 \frac{1}{2} = 1 + \frac{1}{2} = \frac{3}{2}\\
\text{Convert to a common denominator:}\\
\frac{3}{2} + \frac{2}{3} = \frac{3 \cdot 3 + 2 \cdot 2}{2 \cdot 3} = \frac{9 + 4}{6} = \frac{13}{6} = 2 \frac{1}{6}[/tex]
[tex]6. \: \(3 \frac{1}{2} + \frac{4}{5}\)[/tex]
[tex]3 \frac{1}{2} = 3 + \frac{1}{2} = \frac{7}{2}\\
\text{Convert to a common denominator:}\\
\frac{7}{2} + \frac{4}{5} = \frac{7 \cdot 5 + 4 \cdot 2}{2 \cdot 5} = \frac{35 + 8}{10} = \frac{43}{10} = 4 \frac{3}{10}[/tex]
[tex]7. \: \(4 \frac{1}{4} + 2 \frac{1}{6}\)[/tex]
[tex]4 \frac{1}{4} = 4 + \frac{1}{4} = \frac{17}{4}\\
2 \frac{1}{6} = 2 + \frac{1}{6} = \frac{13}{6}\\
\text{Convert to a common denominator:}\\
\frac{17}{4} + \frac{13}{6} = \frac{17 \cdot 3 + 13 \cdot 2}{4 \cdot 6} = \frac{51 + 26}{24} = \frac{77}{24} = 3 \frac{5}{24}
[/tex]
[tex]8. \: \( \frac{5}{6} + 3 \frac{3}{7} \)[/tex]
[tex]3 \frac{3}{7} = 3 + \frac{3}{7} = \frac{24}{7} \\
\text{Convert to a common denominator:} \\
\frac{5}{6} + \frac{24}{7} = \frac{5 \cdot 7 + 24 \cdot 6}{6 \cdot 7} = \frac{35 + 144}{42} = \frac{179}{42} = 4 \frac{11}{42}[/tex]
[tex]9. \: \( 5 \frac{2}{5} + 2 \frac{1}{4} \)[/tex]
[tex]5 \frac{2}{5} = 5 + \frac{2}{5} = \frac{27}{5} \\
2 \frac{1}{4} = 2 + \frac{1}{4} = \frac{9}{4} \\
\text{Convert to a common denominator:} \\
\frac{27}{5} + \frac{9}{4} = \frac{27 \cdot 4 + 9 \cdot 5}{5 \cdot 4} = \frac{108 + 45}{20} = \frac{153}{20} = 7 \frac{13}{20}[/tex]
[tex]10. \: \( 20 \times 3 \frac{1}{9} + \frac{2}{3} \)[/tex]
[tex]3 \frac{1}{9} = 3 + \frac{1}{9} = \frac{28}{9} \\
\text{Multiply by 20:} \\
20 \times \frac{28}{9} = \frac{560}{9} \\
\text{Then add } \frac{2}{3}: \\
\frac{560}{9} + \frac{2}{3} = \frac{560 \cdot 3 + 2 \cdot 9}{9 \cdot 3} = \frac{1680 + 18}{27} = \frac{1698}{27} = 62 \frac{24}{27}[/tex]
[tex]1. \: \(1 \frac{3}{2} + 1 \frac{3}{5} = 4 \frac{1}{10}[/tex]
[tex]2. \: \(\frac{2}{11} + 2 \frac{1}{2} = 2 \frac{15}{22}[/tex]
[tex]3. \: \(1 \frac{1}{3} + \frac{1}{5} = 1 \frac{8}{15}[/tex]
[tex]4. \: \(2 \frac{3}{4} + \frac{2}{2} = 3 \frac{3}{4}[/tex]
[tex]5. \: \(1 \frac{1}{2} + \frac{2}{3} = 2 \frac{1}{6}[/tex]
[tex]6. \: \(3 \frac{1}{2} + \frac{4}{5} = 4 \frac{3}{10}[/tex]
[tex]7. \: \(4 \frac{1}{4} + 2 \frac{1}{6} = 3 \frac{5}{24}[/tex]
[tex]8. \: \( \frac{5}{6} + 3 \frac{3}{7} = 4 \frac{11}{42}[/tex]
[tex]9. \: \(5 \frac{2}{5} + 2 \frac{1}{4} = 7 \frac{13}{20}[/tex]
[tex]10. \: \(20 \times 3 \frac{1}{9} + \frac{2}{3} = 62 \frac{24}{27}[/tex]
Salamat sa iyong aktibong pakikilahok. Patuloy na magtanong at magbahagi ng iyong nalalaman. Sama-sama tayong lumikha ng isang masiglang komunidad ng pagkatuto. IDNStudy.com ang iyong mapagkakatiwalaang kasama para sa lahat ng iyong mga katanungan. Bisitahin kami palagi.
