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Sagot :
Answer:
Given that 12% of the battery is lost every hour, we can model the amount of battery charge remaining as an exponential decay function.
Let's denote:
- ( b(h) ) as the amount of battery charge remaining after \( h \) hours,
- ( b_0 ) as the initial battery charge (100% at ( h = 0 ).
Since 12% of the battery is lost every hour, 88% (100% - 12%) of the battery remains each hour. This gives us a decay factor of 0.88.
The function ( b(h) ) can be represented as:
[tex]b(h) = b_0 \cdot (0.88)^h[/tex]
where:
- ( b_0 ) is the initial battery charge (typically 100%).
To simplify, assuming ( b_0 = 100 ) (100% battery charge):
[tex]b(h) = 100 \cdot (0.88)^h[/tex]
This function ( b(h) ) represents the amount of battery charge left after \( h \) hours, considering a 12% loss of battery per hour.
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