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Completing the square
x²-8x+1​


Sagot :

1. Identify the coefficient of ( x ):

The given expression is ( x² - 8x + 1 \). The coefficient of ( x ) is (-8).

2. Divide the coefficient of ( x ) by 2 and square it:

[tex]\left(\frac{-8}{2}\right)^2 = (-4)^2 = 16[/tex]

3. Add and subtract this square inside the expression:

[tex]x^2 - 8x + 16 - 16 + 1[/tex]

4. Rewrite the expression:

Group the perfect square trinomial and the constants separately:

[tex] (x^2 - 8x + 16) - 16 + 1[/tex]

5. Factor the perfect square trinomial:

[tex] (x - 4)^2 - 15[/tex]

The expression ( x² - 8x + 1 ) can be rewritten by completing the square as:

[tex](x - 4)^2 - 15[/tex]