Sagot :
lII. Draw a related picture for each of the following:
16. A line containing C, A, and R. Give all the possible names of the lines.
- Drawing: Draw a straight line and label three points on it as C, A, and R.
- Possible names: Since a line is defined by any two points on it, the possible names for the line include:
- Line CA
- Line CR
- Line AR
- Line AC
- Line RC
- Line RA
17. A plane M containing points B, U, and S. Give another name for plane M.
- Drawing: Draw a flat surface (plane) and mark three points B, U, and S on it.
- Another name: Since a plane can be named by any three non-collinear points on it, another name for plane M could be `plane BUS`.
18. A point Q on DR but not on RC
- Drawing: Draw a line with points D and R. Mark a point Q on the segment DR such that it does not align with another line RC.
- Point Q: Ensure Q is positioned between D and R but not necessarily in line with R and C.
19. A point T on AM but not on AM
- Clarification Needed: This statement seems contradictory. If it means "a point T on one portion of AM but not on another portion of AM," it suggests splitting line AM into segments.
- Drawing: Draw line AM and mark point T somewhere along it. Indicate that T does not lie on another segment, if such a segment is defined.
20. Two lines that are perpendicular
-Drawing: Draw two lines that intersect at a right angle (90 degrees).
- Perpendicular Lines: Label the lines, for example,
[tex] {line} \( l_1 \) \: and \: line \ \: ( l_2 \), \: showing \: they \: form \: a \: right \: angle \: at \: their \: intersection.
[/tex]
III. Draw a related picture for each of the following:
21. Collinear points A, B, C, D, and E such that:
- AB and AC are opposite rays: A must be between B and C.
- AC and AD are the same rays: C must be between A and D.
- BA and BE are opposite rays: A must be between B and E.
Drawing Steps:
- Draw a straight line and place points in the following order: E, B, A, C, D.
Explanation:
- AB is opposite to AC.
- AC is the same as AD.
- BA is opposite to BE.
22. Collinear points A, B, C, D, and E such that:
- AE + EB = AB: E is between A and B.
- AC + CD = AD: C is between A and D.
- AD + DE = AE: D lies between A and E.
Drawing Steps:
- Draw a straight line and place points in a logical sequence to satisfy these conditions. A possible arrangement could be A, E, B, C, D.
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