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what is the 50th term of an arithmetic sequence if its fifth term is 22 and it's 15th term is 62?​

Sagot :

SOLUTION:

Step 1: Determine the common difference.

aₙ = aₘ + (n - m)d

62 = 22 + (15 - 5)d

62 = 22 + 10d

10d = 62 - 22

10d = 40

10d/10 = 40/10

d = 4

Step 2: Solve for the 50th term.

aₙ = aₘ + (n - m)d

a₅₀ = 62 + (50 - 15)(4)

a₅₀ = 62 + (35)(4)

a₅₀ = 62 + 140

a₅₀ = 202

Hence, the 50th term is 202.