Answer:
To factor the quadratic expression
[tex]2x² - 8x + 9[/tex]
we need to find two numbers that multiply to
[tex](2 \times 9 = 18) and \: add \: up \: to \: (-8).[/tex]
The factors of 18 are:
[tex](1 \times 18), (2 \times 9), and (3 \times 6).[/tex]
If you need to solve it, you can use the quadratic formula:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
For the quadratic equation 2x² - 8x + 9 = 0:
[tex]x = \frac{-(-8) \pm \sqrt{(-8)^2 - 4 \cdot 2 \cdot 9}}{2 \cdot 2}[/tex]
[tex]x = \frac{8 \pm \sqrt{64 - 72}}{4}[/tex]
[tex]x = \frac{8 \pm \sqrt{-8}}{4}[/tex]
