Mishkadaddy18idn
Answered

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Hello! can someone please tell me how to convert this quadratic equation to a standard form? asap! tysm!

given:
6x^2 = 9​

Sagot :

MrChrisidn

Given:

The quadratic equation:

[tex]\bullet \: \: {\bm{6x^{2}=9}}[/tex]

Required:

It is required to convert the quadratic equation to the standard form.

Solution:

Recall that the Standard Form of Quadratic Equation is given as:

[tex]\large{\boxed{\rm{ {ax}^{2} + bx + c = 0}}}[/tex]

Hence, to convert the equation, you'll need to take all terms on the right to the left side. Subtract 9 from both sides to do this:

[tex]\tt{6 {x}^{2} - 9 = 9 - 9}[/tex]

[tex]\large{\tt{ \rightarrow \: \purple{6 {x}^{2} - 9 = 0 }}}[/tex]

Final Answer:

The standard form is [tex]\large{\rm{ \: \purple{6 {x}^{2} - 9 = 0 }}}[/tex].

Tharkieyoidn

The standard form of the quadratic equation is 6x² + 0x - 9 = 0.

Standard Form of Quadratic Equation:

[tex] \begin{gathered} \sf ax {}^{2} + bx + c = 0 \end{gathered}[/tex]

[tex] \boxed {\begin{array}{lcl} \sf Where : \\ \\ \sf \red{ax {}^{2} } - Quadratic \: term \\ \sf \green{bx} \: - Linear \:term \\ \sf {\blue{c}} \: \: \: \: - Constant \: term\end{array}}[/tex]

To convert 6x² = 9 to its standard form, transpose the constant term 9 to the left side of the equation, change its sign, and set it equal to zero. Note that a standard form is always equal to 0.

[tex] \: \: \: \: \: \sf 6x {}^{2} = 9 \rightarrow 6x {}^{2} - 9 = 0[/tex]

We can see that there is still something missing in the equation, which is the linear term (bx). Since there's no linear term, we can represent it as 0x. So the standard form will be written as:

[tex] \begin{gathered} {\boxed {\sf{6x {}^{2} + 0x - 9 = 0}}} \end{gathered}[/tex]