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11th term of _3;6;_12

Sagot :

To find the 11th term of the sequence 3, 6, 12, we need to identify the pattern.

The pattern in this sequence is that each term is double the previous term.

The first term is 3, the second term is 6 (which is 2 times 3), and the third term is 12 (which is 2 times 6).

To find the 11th term, we need to continue doubling the previous term 8 more times.

The 11th term would be:

3 × 2^10 = 3 × 1024 = 3,072

Therefore, the 11th term of the sequence 3, 6, 12 is 3,072.