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Find the missing terms in each arithmetic sequence.
1.3,12,21,_,_,_
2.8,3,-2,_,_
3.5,12,_,26,_

Sagot :

Answer:

  1. 30, 39, 48
  2.  -7, -12
  3. 19, 40

Step-by-step explanation:

To find the missing terms in each arithmetic sequence, we first need to identify the common difference between consecutive terms. The common difference is the constant value added (or subtracted) to each term to get the next term in the sequence.

Sequence 1

  1. 3, 12, 21, _, _, _
  2. Common difference between consecutive terms:      
  3. Missing terms:
  • The fourth term:      
  • The fifth term:      
  • The sixth term:

Sequence 2:

  1. 8, 3, -2, _, _
  2. Common difference between consecutive terms:      
  3. Missing terms:
  • The fourth term:      
  • The fifth term:      

Sequence 3:

  1. 5, 12, _, 26, _
  2. Common difference between consecutive terms:
  • First pair:      
  • Second pair:      

3. Missing terms:

  • The third term:      
  • The fifth term:

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Answer:

1) 3,12,21,30,39,48

2.)8,3,-2,-7,-12

3.)5,12,19,26,33

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Step-by-step explanation:

Sequence 1: (3, 12, 21, _, _, _)

The given terms are

The common difference (d = 12 - 3 = 9).

The missing terms are:

21 + 9 = 30

30 + 9 = 39

39 + 9 = 48

Sequence 2: (8, 3, -2, _, _)

The given terms are (8, 3, -2).

The common difference (d = 3 - 8 = -5).

The missing terms are:

-2 + (-5) = -7

- 7 + (-5) = -12

Sequence 3: (5, 12, _, 26, _)

The given terms are (5, 12, 26).

The common difference (d = 12 - 5 = 7).

The missing terms are:

12 + 7 = 19

26 + 7 = 33