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Answer:
(i) Expand xx2x:
xx2x = x * x * 2 * x
= x^2 * 2 * x (Combine the x terms)
= 2x^3 (Multiply the coefficients and add the exponents)
Therefore, the expanded form of xx2x is 2x^3.
(ii) Expand 2x x 3y:
2x x 3y = 2x * 3y
= 6xy (Multiply the coefficients)
Therefore, the expanded form of 2x x 3y is 6xy.