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1.
Expand
(i) xx2x
(ii) 2x x 3y


Sagot :

Answer:

(i) Expand xx2x:

xx2x = x * x * 2 * x

= x^2 * 2 * x (Combine the x terms)

= 2x^3 (Multiply the coefficients and add the exponents)

Therefore, the expanded form of xx2x is 2x^3.

(ii) Expand 2x x 3y:

2x x 3y = 2x * 3y

= 6xy (Multiply the coefficients)

Therefore, the expanded form of 2x x 3y is 6xy.