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Answer:
If Ms. Sanes' class has 35 pupils and they are lining up in pairs, each pupil will have a partner. Since there are an odd number of pupils (35 is not divisible by 2), there will be one pupil left without a partner at the end of the line. However, all the other pupils will be paired up.
If there are only 30 pupils in the class, each pupil will still have a partner. This is because 30 is an even number and can be evenly divided by 2, resulting in 15 pairs. In this case, no student would be left without a partner in the lineup.
Answer:
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1. If there are 35 pupils:
- 35 is an odd number.
- If you try to pair up the pupils, there will be one pupil left without a partner because odd numbers cannot be divided into pairs without leaving a remainder.
2. If there are 30 pupils:
- 30 is an even number.
- If you try to pair up the pupils, each pupil will have a partner because even numbers can be divided into pairs without leaving a remainder.
- With 35 pupils, not every pupil will have a partner because 35 is odd.
- With 30 pupils, every pupil will have a partner because 30 is even.