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Answer:
To calculate the area of the TV set when \( x = 5 \text{ cm} \), we need to know the relationship between \( x \) and the dimensions of the TV.
Assuming that the TV's dimensions are given by \( x \) and \( y \), and \( x \) represents the length (or one dimension), and \( y \) represents the width, we need to know the value of \( y \).
If we don't have the value of \( y \), we can consider a hypothetical scenario where both dimensions are proportional to \( x \).
For example, if the width \( y \) is some multiple of \( x \) (say \( y = k \cdot x \) where \( k \) is a constant), we can then calculate the area.
Let's assume \( k = 2 \), meaning the width is twice the length:
\[ \text{Width } y = 2 \cdot x \]
Then, the area \( A \) of the TV set would be:
\[ A = x \cdot y \]
\[ A = x \cdot (2 \cdot x) \]
\[ A = 2x^2 \]
When \( x = 5 \text{ cm} \):
\[ A = 2 \cdot (5 \text{ cm})^2 \]
\[ A = 2 \cdot 25 \text{ cm}^2 \]
\[ A = 50 \text{ cm}^2 \]
Therefore, the area of the TV set when \( x = 5 \text{ cm} \) would be \( 50 \text{ cm}^2 \), assuming the width is twice the length. If you have specific values or a different relationship, please provide those details for a more accurate calculation.