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A body is projected horizontally from the top of a tower with a velocity of 20m/s it landed on a grand level at a horizontal distance of 60m from the foot of the tower. Calculate the height of the tower (g=10m/s²)

Sagot :

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Solution

To calculate the height of the tower, we can use the equations of motion for a projectile launched horizontally.

Given:

- Initial velocity (v₀) = 20 m/s

- Horizontal distance (d) = 60 m

- Acceleration due to gravity (g) = 10 m/s²

The height of the tower (h) can be calculated using the following equation:

h = (v₀²) / (2g)

Substituting the given values:

h = (20 m/s)² / (2 × 10 m/s²)

h = 400 m² / 20 m/s²

h = 20 m

Therefore, the height of the tower is 20 meters.

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