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A hobby rocket reaches a height of 88.5 and lands 136 from the launch point with no air resistance. What was the angle of launch?

Sagot :

Justanormalgirl82idn

The angle of launch was 54.5 degrees.

This can be calculated using the components of the rocket's motion. The horizontal distance traveled can be represented by the equation:

x = V₀ * t * cos(θ)

where x is the horizontal distance (136m), V₀ is the initial velocity, t is the time of flight, and θ is the launch angle.

Similarly, the vertical distance can be represented by the equation:

y = V₀ * t * sin(θ) - 0.5 * g * t^2

where y is the vertical distance (88.5m), g is the acceleration due to gravity (9.81 m/s^2). Solving for the launch angle θ, we find that it is approximately 54.5 degrees.

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