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A line contains the points (8,3) and (-4,9). What is the equation of line

A. Y=2x+7

B. Y=-1/2x+7

C. Y=-2x+7

D. Y=1/2x+7.


Sagot :

Answer:

[tex]{\huge\color{yellow}{\boxed{\fcolorbox{yellow}{purple}{Pa Brainliest}}}}[/tex]

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1. Calculate the slope (m):

The slope of a line passing through two points:

[tex] \((x_1, y_1)\) and \((x_2, y_2)\) is given by[/tex]

[tex] \[

m = \frac{y_2 - y_1}{x_2 - x_1}

\][/tex]

[tex]Plugging in the given points \((8, 3)\) and \((-4, 9)\):

\[

m = \frac{9 - 3}{-4 - 8} = \frac{6}{-12} = -\frac{1}{2}

\][/tex]

2. Use the point-slope form of the equation:

The point-slope form of a line's equation is:

[tex] \[

y - y_1 = m(x - x_1)

\]

[/tex]

[tex]Using the point \((8, 3)\) and the slope [/tex]

[tex]\(m = -\frac{1}{2}\):[/tex]

[tex]

\[

y - 3 = -\frac{1}{2}(x - 8)

\][/tex]

3. Simplify to the slope-intercept form

[tex](y = mx + b)[/tex]

Distribute the slope and simplify:

[tex]\[

y - 3 = -\frac{1}{2}x + 4

\][/tex]

Add 3 to both sides to solve for

[tex]\(y\):

\[

y = -\frac{1}{2}x + 4 + 3

\]

\[

y = -\frac{1}{2}x + 7

\][/tex]

So the equation of the line is

[tex]\(y = -\frac{1}{2}x + 7\),[/tex]

which corresponds to option B:

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[tex]B. \(Y = -\frac{1}{2}x + 7\)[/tex]

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