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Answer:
Here's how we solve the given integral:
∫ (x^3 + 2x^2) / (x * 4 * (sqrt(x + 2) * log(3)) dx, from 1 to 3
First, we can simplify the expression in the numerator: (x^3 + 2x^2)/x = x^2 + 2
Then, using the FTC, we can integrate as follows:
∫ (x^2 + 2) / (4 * sqrt(x + 2) * log(3)) dx
= (1/4) ∫ (x^2