[tex]\underline{\underline{\large{\red{\mathcal{✒GIVEN:}}}}}[/tex]
[tex]\bullet \: \: \rm{sin= 30^{\circ}}[/tex]
[tex]\underline{\underline{\large{\red{\mathcal{REQUIRED:}}}}}[/tex]
Solve the trigonometry
[tex]\underline{\underline{\large{\red{\mathcal{SOLUTION:}}}}}[/tex]
Consider the [tex]\tt{\purple{30^{\circ} -60^{\circ} -90^{\circ} \: Right \: Triangle}}[/tex] in the given.
Which:
[tex]\bullet \: \: \rm{opposite=1}[/tex]
[tex]\bullet \: \: \rm{adjacent= \sqrt{3} }[/tex]
[tex]\bullet \: \: \rm{longest \: side= 2 }[/tex]
Remember, the trigonometric ratio or [tex]\tt{\purple{SOH-CAH-TOA}}[/tex]
[tex]\small{\boxed{ \bm{{ \red{ \sin \theta = \dfrac{opposite}{hypøtèńuse} }}}}}[/tex]
Substitute:
[tex]\tt{ \sin 30^{\circ} = \large{ \tt {\purple{\dfrac{1}{2} }}}}[/tex]
Final Answer:
[tex]\large{ \rm \sin = {\purple{\dfrac{1}{2} }}}[/tex]
