Answered

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a steady current of 2A is passed through a solution contain ions of a metal M² for a nine minutes. The mass of metal M that is liberated is 0.3552g.Identify element M.

Sagot :

Kenjinxidn

[tex]\sf{﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌}[/tex]

[tex]\bold{\huge{ANSWER:}}[/tex]

[tex]\boxed{\sf\green{✓}}[/tex] To identify the element M, we need to use Faraday's laws of electrolysis.

ׂ╰┈➤ The mass of metal M deposited is directly proportional to the charge passed through the solution.

ׂ╰┈➤ The charge passed is given by the product of the current and time:

  • Q = I × t
  • = 2 A × 9 min
  • = 18 C

ׂ╰┈➤ The mass of metal M deposited is given by:

  • m = Z × Q
  • where Z is the equivalent weight of the metal.

ׂ╰┈➤ The equivalent weight of a metal is the mass of the metal that can be deposited by one Faraday (96,485 C).

  • Therefore, we can set up the following equation:
  • 0.3552 g = Z × 18 C

ׂ╰┈➤ To find the equivalent weight Z, we can divide both sides by 18 C:

  • Z = 0.3552 g / 18 C
  • Z ≈ 19.7 g/mol

✎ The equivalent weight of the metal is approximately [tex]\sf\red{19.7~g/mol}[/tex].

[tex]\boxed{\sf\green{✓}}[/tex] This is the equivalent weight of copper, so the metal M is [tex]\sf\red{copper}[/tex].

╰─▸ ❝ @kenjinx

[tex]\sf{﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌}[/tex]

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