PROBLEM SOLVING
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[tex]\rm{\underline{QUESTION:}}[/tex]
You go to the store with x money. I spent half of my money and P10 more. I had exactly P30 left. How much money did I have at first?
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[tex]\rm{\underline{SOLUTION:}}[/tex]
Let x be the unknown amount of money. Based on your given problem,
- You spent half of your money. This can be expressed as [tex]\frac{x}{2}[/tex], where x is the unkown number divided by 2.
- You spent P10 more and had exactly P30 left.
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So our equation will be:
- [tex]x - (\frac{x}{2} + 10) = 30[/tex]
Solving for x:
- [tex]x - (\frac{x}{2} + 10) = 30[/tex]
- [tex]x - \frac{x}{2} - 10 = 30[/tex]
- [tex]\frac{2x}{2} - \frac{x}{2} - 10 = 30[/tex]
- [tex]\frac{x}{2} - 10 = 30[/tex]
- [tex]{\frac{x}{2} - 10 + 10 = 30+10}[/tex]
- [tex]\frac{x}{2} =40[/tex]
Lastly, multiply both sides by 2 to find x. The other half of your spent money will be found by multiplying.
- [tex]{\frac{x}{2} \times 2=40 \times 2}[/tex]
- [tex]x = \green{80}[/tex]
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Hence, you had P80 before going to the store.
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[tex]\large{\boxed{\tt{\blue{06/17/2024}}}}[/tex]
