Makahanap ng mabilis na mga solusyon sa iyong mga problema sa IDNStudy.com. Ang aming platform ay nagbibigay ng mga maaasahang sagot upang matulungan kang gumawa ng matalinong desisyon nang mabilis at madali.
Sagot :
Answer:
[tex]{\small\color{yellow}{\boxed{\fcolorbox{yellow}{purple}{ℙ }}}}[/tex]
a) Percentage Composition:
1. Oxygen in Sulphuric Acid (H2SO4):
- Molecular mass of H2SO4 = 2(1) + 32 + 4(16) = 98 g/mol
- Oxygen's contribution = (4 * 16) / 98 * 100% = 64/98 * 100% ≈ 65.31%
2. Carbon in Sugar:
- There are different types of sugar, but for simplicity, let's consider sucrose (table sugar) with the formula C12H22O11.
- Molecular mass of C12H22O11 = 12(12) + 22(1) + 11(16) = 342 g/mol
- Carbon's contribution = (12 * 12) / 342 * 100% ≈ 42.11%
_______________________________
b) Empirical Formulas:
1. Benzene (C6H6):
- The empirical formula is the simplest whole number ratio of atoms in a compound, so for benzene, C6H6, the ratio is 1:1, making the empirical formula CH.
2. Sugar (assuming sucrose, C12H22O11):
- The empirical formula of sugar is CH2O.
3. Hydrogen Peroxide (H2O2):
- The empirical formula of hydrogen peroxide is HO.
_______________________________
QI. Molecular Mass Calculation:
3. Sodium Zincate (Na2ZnO2):
- Molecular mass = 2(23) + 65 + 2(16) = 23 + 23 + 65 + 32 = 143 g/mol
4. Aluminium Nitride (AlN):
- Molecular mass = 27 + 14 = 41 g/mol
5. Ferrous Chloride (FeCl2):
- Molecular mass = 56 + 2(35.5) = 56 + 71 = 127 g/mol
______________________________________
I hope this breakdown helps.
Pinahahalagahan namin ang bawat tanong at sagot na iyong ibinabahagi. Patuloy na maging aktibo at magbahagi ng iyong karanasan. Sama-sama tayong magtatagumpay. Ang IDNStudy.com ay laging nandito upang tumulong sa iyo. Bumalik ka palagi para sa mga sagot sa iyong mga katanungan.