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Complete the given ordered pairs so that each is a solution of the given equation.

A. 3x + 5y = 15
(?, 3) (5, ?) (?, -3)

B. 5x - 4y = -16
(0, ?) (4, ?) (?, 14)

C. 3x - y = 3
(?, 0) (? 3) (1, ?)

Complete solution po dapat. Report ko kung hindi. ​

Sagot :

Zenzieeidn

LINEAR EQUATIONS

Answer:

A. Linear Pair (3x + 5y = 15)

  1. (0,3)
  2. (5,0)
  3. (10, -3)

B. Linear Pair (5x - 4y = -16)

  1. (0,4)
  2. (4,9)
  3. (8,14)

C. Linear Pair (3x - y = 3)

  1. (1,0)
  2. (2,3)
  3. (1,0)

Step-by-step explanation:

Substitute the given values in order to find the missing terms in the given linear equations.

A. Linear Pair (3x + 5y = 15)

1. (_,3) y = 3

  • [tex]3x + 5y = 15[/tex]

  • [tex]3x + 5(3) = 15[/tex]

  • [tex]3x + 15 = 15[/tex]

  • [tex]3x = 15 - 15[/tex]

  • [tex] \frac{ \cancel3x}{ \cancel3} = \frac{0}{3} [/tex]

  • [tex]x = 0[/tex]

2. (5,_) x = 5

  • [tex]3x + 5y = 15[/tex]

  • [tex]3(5) + 5y = 15[/tex]

  • [tex]15 + 5y = 15[/tex]

  • [tex]5y = 15 - 15[/tex]

  • [tex] \frac{ \cancel5y}{ \cancel5} = \frac{0}{5} [/tex]

  • [tex]y = 0[/tex]

3. (_, -3) y = -3

  • [tex]3x + 5y = 15[/tex]

  • [tex]3x + 5( - 3) = 15[/tex]

  • [tex]3x - 15 = 15[/tex]

  • [tex]3x = 15 + 15[/tex]

  • [tex] \frac{\cancel3x}{\cancel3} = \frac{30}{3} [/tex]

  • [tex]x = 10[/tex]

B. Linear Pair (5x - 4y = -16)

1. (0,_) x = 0

  • [tex]5x - 4y = - 16[/tex]

  • [tex]5(0) - 4y = - 16[/tex]

  • [tex]0 - 4y = - 16[/tex]

  • [tex] - 4y = - 16 + 0[/tex]

  • [tex] \frac{ \cancel{- 4}y}{ \cancel{- 4}} = \frac{ - 16}{ - 4} [/tex]

  • [tex]y = 4[/tex]

2. (4,_) x = 4

  • [tex]5x - 4y = - 16[/tex]

  • [tex]5(4) - 4y = - 16[/tex]

  • [tex]20 - 4y = - 16[/tex]

  • [tex] - 4y = - 16 - 20[/tex]

  • [tex] - 4y = - 36[/tex]

  • [tex] \frac{ \cancel{- 4}y}{ \cancel{- 4}} = \frac{ - 36}{ - 4} [/tex]

  • [tex]y = 9[/tex]

3. (_,14) y = 14

  • [tex]5x - 4y = - 16[/tex]

  • [tex]5x - 4(14) = - 16[/tex]

  • [tex]5x - 56 = - 16[/tex]

  • [tex]5x = - 16 + 56[/tex]

  • [tex] \frac{ \cancel{ 5}x}{ \cancel{5}} = \frac{ 40}{ 5} [/tex]

  • [tex]x = 8[/tex]

C. Linear Pair (3x - y = 3)

1. (_,0) y = 0

  • [tex]3x - y = 3[/tex]

  • [tex]3x - 0 = 3[/tex]

  • [tex]3x = 3 + 0[/tex]

  • [tex] \frac{ \cancel3x}{ \cancel3} = \frac{3}{3} [/tex]

  • [tex]x = 1[/tex]

2. (_,3) y = 3

  • [tex]3x - y = 3[/tex]

  • [tex]3x - 3 = 3[/tex]

  • [tex]3x = 3 + 3[/tex]

  • [tex] \frac{ \cancel3x}{ \cancel3} = \frac{6}{3} [/tex]

  • [tex]x = 2[/tex]

3. (1,_) x = 1

  • [tex]3(1) - y = 3[/tex]

  • [tex]3 - y = 3[/tex]

  • [tex] - y = 3 - 3[/tex]

  • [tex] \frac{ \cancel{-1 }y}{ \cancel{- 1}} = \frac{0}{ - 1} [/tex]

  • [tex]y = 0[/tex]