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Mr. Lim and Mr. Tay had $ 31,090 at first. Mr. Lim donated $2390 of his money
and Mr. Tay spent half of his money on a holiday trip. As a result, Mr. Lim had 3
times as much money as Mr. Tay. How much money did Mr. Lim have at first?
​

Sagot :

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Answer: Let's break down the problem step by step.

1. Initially, Mr. Lim and Mr. Tay had a total of $31,090.

2. Mr. Lim donated $2390 of his money, so he had $31,090 - $2390 = $28,700 left.

3. Mr. Tay spent half of his money on a holiday trip. So, he had $31,090 / 2 = $15,545 left.

4. We're given that Mr. Lim had three times as much money as Mr. Tay after these transactions.

5. Let's denote the amount of money Mr. Tay had initially as \( x \). Then, Mr. Lim initially had \( 3x \) dollars.

6. After the transactions, Mr. Lim had $28,700 and Mr. Tay had $15,545.

7. So, we can set up the equation:

\[3x = 28,700\]

\[x = \frac{28,700}{3}\]

\[x = 9566.67\]

Now, we know that Mr. Lim initially had \(3x\) dollars. So,

\[3 \times 9566.67 = 28,700\]

Thus, Mr. Lim initially had $28,700.

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