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A teacher accidently knocks a mug of coffee off their desk. If the mug was hit form its side so that it flies off the desk is 0. 75 m tall how long will it take for the mug to hit the ground?

Sagot :

Vi = Vi + at

∆y = ViL + 1/2 at²

V(làmb-da)² = Vi2 + 2a∆x

V(làmb-da) + Vi/2 = ∆x/t

ay = 9.8 m/s²

Vi = 0.3 m/s

- Vi,x = 0.3 m/s

- Vi,y ° 0 m/s

∆y2 = 0.75m

∆y = Vi-yt + 1/2 ay t²

- 0.75m = (0°ms) t + 1/2 (-9.8 ms²) t2

-0.75m/-4.4 ms2 = (-4.9ms²) t2/-4.9 ms

√0.153s² = √t²

0.39s = t is the FINAL ANSWER.