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1. Energy required to heat the water:
Energy = 8.5 kg * 4180 J/kg K * (43°C - 18°C)
Energy = 8.5 kg * 4180 J/kg K * 25°C
Energy = 8.5 kg * 4180 J/kg K * 25
Energy = 8.5 kg * 104,500 J
Energy = 893,250 J
2. Convert energy to kilowatt-hours:
Energy (kWh) = 893,250 J / (3.6 x 10^6 J)
Energy (kWh) = 0.248125 kWh
3. Calculate the cost:
Cost = 0.248125 kWh * Php 11.32/kWh
Cost = Php 2.81
it would cost Php 2.81 to heat 8.5 kg of water from 18°C to 43°C using an electric water heater.