Answered

IDNStudy.com, ang iyong mapagkukunan ng eksaktong at maaasahang mga sagot. Alamin ang mga detalyadong sagot mula sa mga bihasang miyembro ng aming komunidad na sumasaklaw sa iba't ibang paksa para sa lahat ng iyong pangangailangan.

Calculate the buoyant force of a gold statue with a mass of 1.25 x105 grams and a density of 19,300 kg/m when fully submerged in water with density of 1000 kg/m3

Sagot :

Ash1289idn

To calculate the buoyant force acting on the gold statue when fully submerged in water, we can use the following formula:

Buoyant force = Volume of the object submerged in the fluid x Density of the fluid x Acceleration due to gravity

First, we need to convert the mass of the gold statue from grams to kilograms:

1.25 x 10^5 grams = 125,000 grams = 125 kg

Next, we can calculate the volume of the gold statue submerged in water using its mass and density:

Density of gold statue = 19,300 kg/m^3

Mass of gold statue = 125 kg

Volume = Mass / Density

Volume = 125 kg / 19,300 kg/m^3

Volume ≈ 0.00648 m^3

Now, we can calculate the buoyant force:

Buoyant force = Volume x Density of water x Acceleration due to gravity

Buoyant force = 0.00648 m^3 x 1000 kg/m^3 x 9.81 m/s^2

Buoyant force ≈ 63.7221 N

Therefore, the buoyant force acting on the gold statue when fully submerged in water is approximately 63.72 Newtons.

꒰⁠⑅⁠ᵕ⁠༚⁠ᵕ⁠꒱⁠˖

Ang iyong aktibong pakikilahok ay mahalaga sa amin. Magpatuloy sa pagtatanong at pagbahagi ng iyong nalalaman. Sama-sama tayong lumikha ng isang masiglang komunidad ng pagkatuto. Para sa mabilis at eksaktong mga solusyon, isipin ang IDNStudy.com. Salamat sa iyong pagbisita at sa muling pagkikita.